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Diffstat (limited to 'electronics/test/2/test.txt')
| -rw-r--r-- | electronics/test/2/test.txt | 44 |
1 files changed, 44 insertions, 0 deletions
diff --git a/electronics/test/2/test.txt b/electronics/test/2/test.txt new file mode 100644 index 0000000..3d7c2fa --- /dev/null +++ b/electronics/test/2/test.txt @@ -0,0 +1,44 @@ +1)a)i) in book +1)a)ii) in book +1)a)iii) in book + +1)b) in book + +1)c)i) in book +1)c)ii) in book +1)c)iii) in book +1)c)iv) in book + +2)a)i) forward +2)a)ii) reverse +2)a)iii) reverse +2)a)iv) forward +2)b) in book +2)c)i) in book +2)c)ii) in book +2)c)iii) in book +2)c)iv) in book + +3)a) in book +3)b) in book + +4)a)i) in book +4)a)ii) I believe it would be close to 0V as the input of 100Hz is very low, and this is a high pass filter meaning only high frequency signals should pass through +4)b) They can have a gain greater than 1, they can be stricter (have a sharper cut off, higher Q factor), than a passive filter +4)c)i) in book +4)c)ii) in book + +5) +- the diode must be between the mesurment middle point and point C, this is because there is 0 current flowing when C is connected to 9V +- you can also tell this because current flows from A-B and B-A just fine +- there is a resistor going from A to the mid point, and from B to the mid point +- the resistor from A to the mid point must be 100 ohms, this is because there R = V/I, we can use the result from A-C (resistor through diode) to tell that V = 9 - 0.7 and the table to tell us that I = 0.083 which gives us 100 ohms +- the resistor from B to the mid point must be 100 ohms, this is because there R = V/I, we can use the result from B-C (resistor through diode) to tell that V = 9 - 0.7 and the table to tell us that I = 0.0415 which gives us 200 ohms +- this can be confirmed by the fact that using the table values fro A-B or B-A, we can say 9/0.3 to get the resistance or Ra + Rb which is 300 ohms, thus confirming our result from before + + + + + + + |