From fed4285a51b874113c41d9a9e78810640d71e5dc Mon Sep 17 00:00:00 2001 From: thing1 Date: Wed, 12 Mar 2025 11:30:18 +0000 Subject: to much work --- electronics/test/1/test.year2.txt | 35 ++++++++++++++++++++++++++++++ electronics/test/1/test2.year2.txt | 40 ++++++++++++++++++++++++++++++++++ electronics/test/2/test.2.txt | 33 ++++++++++++++++++++++++++++ electronics/test/2/test.txt | 44 ++++++++++++++++++++++++++++++++++++++ electronics/test/test.year2.txt | 35 ------------------------------ electronics/test/test2.year2.txt | 40 ---------------------------------- 6 files changed, 152 insertions(+), 75 deletions(-) create mode 100644 electronics/test/1/test.year2.txt create mode 100644 electronics/test/1/test2.year2.txt create mode 100644 electronics/test/2/test.2.txt create mode 100644 electronics/test/2/test.txt delete mode 100644 electronics/test/test.year2.txt delete mode 100644 electronics/test/test2.year2.txt (limited to 'electronics/test') diff --git a/electronics/test/1/test.year2.txt b/electronics/test/1/test.year2.txt new file mode 100644 index 0000000..4598a82 --- /dev/null +++ b/electronics/test/1/test.year2.txt @@ -0,0 +1,35 @@ +Lucas standen electronics test 1 year 2 + +1)a)i) in book +1)a)ii) in book +1)a)iii) in book +1)b) in book + +2)a) in book +2)b) in book +2)c) in book +2)c)i) in book +2)c)ii) in book +2)c)iii) in book + +3)a) in book +3)b) The red LED will be on as the amp will be outputing 11V (see diagram for workings), which would mean that +over the green led and resistor is only 1V which wont be enough to light the LED, however over the red LED and +resistor, is 11V which is enough to light the led +3)c)i) in book +3)c)ii) in book +3)c)iii) R2 will recive a higher current than R1 as it has the higher resistance and it is in parralel with R1 +meaning the current splits between them proportional to resistance + +4)a) in book +4)b)i) in book +4)b)ii) a ripple counter will move upwards/downwards when the previce dtype has changed state, however a +syncrhronos counter will count using a logic system from the clock and other outputs, (avoids propigation +delay, and makes all outputs change at the same time whereas an asynchronos counter will change its outputs +change at different times) +4)c) in book +4)d) in book + + + + diff --git a/electronics/test/1/test2.year2.txt b/electronics/test/1/test2.year2.txt new file mode 100644 index 0000000..203e5c1 --- /dev/null +++ b/electronics/test/1/test2.year2.txt @@ -0,0 +1,40 @@ +5) +the circit should work at night as, the ldr will dawf the other resistor + +the circit will not work at day as the ldr is still 400 OHM's which is +higher than the 100 OHM resistor + +because the bulb has a resistance of 100 OHM's it will not work as expected + +this will cause the bulb to never be properly on as the resistance in the bulbs branch +will limit the voltage through it to be <100 OHM's and thus it wont get 6V over it + +to fix this a voltage follower can be place between the bulb and the potential divider +to keep the impedances at the right locations + +(see book for details) +6)a)i) in book +6)a)ii) in book +6)a)iii) when the switch is releases the voltage over the capacitor will be at 8.65 V +this will mean the led is on. +when it falls to 6V the capacitor will make the logic gate switch 3.34 seconds after the switch +is released, this will cause the not gate to switch and the led to be on +6)b)i) in book +6)b)ii) in book + +7)a) in book +7)b)i) in book +7)b)ii) in book +7)b)iii) in book +7)b)iv) in book +7)b)v) in book + +8)a) in book +8b) in book +8)c)i) because it has a higher input imedance +8)c)ii) in book +8)c)iii) in book +8)d)i) in book +8)d)ii) to smooth the signal of noise +8)d)iii) in book +8)d)e) in book diff --git a/electronics/test/2/test.2.txt b/electronics/test/2/test.2.txt new file mode 100644 index 0000000..b423d97 --- /dev/null +++ b/electronics/test/2/test.2.txt @@ -0,0 +1,33 @@ +6)a)i) in book +6)a)ii) To ensure that there is no loading effect caused by the low output impedance of the microphone +6)b)i) in book +6)b)ii) in book + +7)a)i) in book +7)a)ii) because random noise will slightly adjust the height of the peeks, which in PPM doesn't change the encoded data, while in PAM the height of the peaks does effect the encoded data (because the amplitute stores the signal) +7)b)i) in book +7)b)ii) in book +7)b)iii) a number is taken in parralel, and is put into a shift register. Each bit is shifted down through the registers, in the graphs, through to register D, where it is then sent as an individual pulse down the serial wire, this process is repeated by shifting each register down. + +8)a) in book +8)b)i) in book +8)b)ii) in book +8)b)iii) This is because all the current in the system must flow through the 10 Ohm resistor to get to the other components. +8)c)i) in book +8)c)ii) in book +8)c)iii) It wouldn't recive the correct volatage or current values, as the ripple voltage is too high, and thus the zenner wont always be working with the desired power +8)d)i) this would remove (most of) the ripple and allow the user to set the voltage to a fixed value +8)d)i) in book + +9)a) S1 and S2 are both triggers for the system, if either of them are pressed the thyristor will turn on, thus making the alarm set off. There are 2 switches to allow for multiple alarm points (perhaps one on each door). S3 will turn of the alarm +9)b) in book +9)c) in book +9)d)i) S3 is pressed +9)d)ii) at the start, before Y dips to 0V, the alarm is turned on and the thyristor is conducting, this is because there is 0V over the thyristor, which means all 12V must be over the alarm, turning it on. When S3 is pressed (Y dips to 0V) the alarm will turn off because the thyristor has been reset. It will now have 12V over it until the alarm is triggered again either by S1 or S2 + +10)a)i) this is interference, an unwanted signal being applied over the top of the desired signal, an example of this is a strong magnet, as when moved over a wire, they can change the voltages, thus applying a noise to the signal +10)a)ii) in book +10)b)i) in book +10)b)ii) in book +10)b)iii) in book + diff --git a/electronics/test/2/test.txt b/electronics/test/2/test.txt new file mode 100644 index 0000000..3d7c2fa --- /dev/null +++ b/electronics/test/2/test.txt @@ -0,0 +1,44 @@ +1)a)i) in book +1)a)ii) in book +1)a)iii) in book + +1)b) in book + +1)c)i) in book +1)c)ii) in book +1)c)iii) in book +1)c)iv) in book + +2)a)i) forward +2)a)ii) reverse +2)a)iii) reverse +2)a)iv) forward +2)b) in book +2)c)i) in book +2)c)ii) in book +2)c)iii) in book +2)c)iv) in book + +3)a) in book +3)b) in book + +4)a)i) in book +4)a)ii) I believe it would be close to 0V as the input of 100Hz is very low, and this is a high pass filter meaning only high frequency signals should pass through +4)b) They can have a gain greater than 1, they can be stricter (have a sharper cut off, higher Q factor), than a passive filter +4)c)i) in book +4)c)ii) in book + +5) +- the diode must be between the mesurment middle point and point C, this is because there is 0 current flowing when C is connected to 9V +- you can also tell this because current flows from A-B and B-A just fine +- there is a resistor going from A to the mid point, and from B to the mid point +- the resistor from A to the mid point must be 100 ohms, this is because there R = V/I, we can use the result from A-C (resistor through diode) to tell that V = 9 - 0.7 and the table to tell us that I = 0.083 which gives us 100 ohms +- the resistor from B to the mid point must be 100 ohms, this is because there R = V/I, we can use the result from B-C (resistor through diode) to tell that V = 9 - 0.7 and the table to tell us that I = 0.0415 which gives us 200 ohms +- this can be confirmed by the fact that using the table values fro A-B or B-A, we can say 9/0.3 to get the resistance or Ra + Rb which is 300 ohms, thus confirming our result from before + + + + + + + diff --git a/electronics/test/test.year2.txt b/electronics/test/test.year2.txt deleted file mode 100644 index 4598a82..0000000 --- a/electronics/test/test.year2.txt +++ /dev/null @@ -1,35 +0,0 @@ -Lucas standen electronics test 1 year 2 - -1)a)i) in book -1)a)ii) in book -1)a)iii) in book -1)b) in book - -2)a) in book -2)b) in book -2)c) in book -2)c)i) in book -2)c)ii) in book -2)c)iii) in book - -3)a) in book -3)b) The red LED will be on as the amp will be outputing 11V (see diagram for workings), which would mean that -over the green led and resistor is only 1V which wont be enough to light the LED, however over the red LED and -resistor, is 11V which is enough to light the led -3)c)i) in book -3)c)ii) in book -3)c)iii) R2 will recive a higher current than R1 as it has the higher resistance and it is in parralel with R1 -meaning the current splits between them proportional to resistance - -4)a) in book -4)b)i) in book -4)b)ii) a ripple counter will move upwards/downwards when the previce dtype has changed state, however a -syncrhronos counter will count using a logic system from the clock and other outputs, (avoids propigation -delay, and makes all outputs change at the same time whereas an asynchronos counter will change its outputs -change at different times) -4)c) in book -4)d) in book - - - - diff --git a/electronics/test/test2.year2.txt b/electronics/test/test2.year2.txt deleted file mode 100644 index 203e5c1..0000000 --- a/electronics/test/test2.year2.txt +++ /dev/null @@ -1,40 +0,0 @@ -5) -the circit should work at night as, the ldr will dawf the other resistor - -the circit will not work at day as the ldr is still 400 OHM's which is -higher than the 100 OHM resistor - -because the bulb has a resistance of 100 OHM's it will not work as expected - -this will cause the bulb to never be properly on as the resistance in the bulbs branch -will limit the voltage through it to be <100 OHM's and thus it wont get 6V over it - -to fix this a voltage follower can be place between the bulb and the potential divider -to keep the impedances at the right locations - -(see book for details) -6)a)i) in book -6)a)ii) in book -6)a)iii) when the switch is releases the voltage over the capacitor will be at 8.65 V -this will mean the led is on. -when it falls to 6V the capacitor will make the logic gate switch 3.34 seconds after the switch -is released, this will cause the not gate to switch and the led to be on -6)b)i) in book -6)b)ii) in book - -7)a) in book -7)b)i) in book -7)b)ii) in book -7)b)iii) in book -7)b)iv) in book -7)b)v) in book - -8)a) in book -8b) in book -8)c)i) because it has a higher input imedance -8)c)ii) in book -8)c)iii) in book -8)d)i) in book -8)d)ii) to smooth the signal of noise -8)d)iii) in book -8)d)e) in book -- cgit v1.2.3