diff options
Diffstat (limited to 'electronics/test/2')
| -rw-r--r-- | electronics/test/2/test.2.txt | 33 | ||||
| -rw-r--r-- | electronics/test/2/test.txt | 44 |
2 files changed, 77 insertions, 0 deletions
diff --git a/electronics/test/2/test.2.txt b/electronics/test/2/test.2.txt new file mode 100644 index 0000000..b423d97 --- /dev/null +++ b/electronics/test/2/test.2.txt @@ -0,0 +1,33 @@ +6)a)i) in book +6)a)ii) To ensure that there is no loading effect caused by the low output impedance of the microphone +6)b)i) in book +6)b)ii) in book + +7)a)i) in book +7)a)ii) because random noise will slightly adjust the height of the peeks, which in PPM doesn't change the encoded data, while in PAM the height of the peaks does effect the encoded data (because the amplitute stores the signal) +7)b)i) in book +7)b)ii) in book +7)b)iii) a number is taken in parralel, and is put into a shift register. Each bit is shifted down through the registers, in the graphs, through to register D, where it is then sent as an individual pulse down the serial wire, this process is repeated by shifting each register down. + +8)a) in book +8)b)i) in book +8)b)ii) in book +8)b)iii) This is because all the current in the system must flow through the 10 Ohm resistor to get to the other components. +8)c)i) in book +8)c)ii) in book +8)c)iii) It wouldn't recive the correct volatage or current values, as the ripple voltage is too high, and thus the zenner wont always be working with the desired power +8)d)i) this would remove (most of) the ripple and allow the user to set the voltage to a fixed value +8)d)i) in book + +9)a) S1 and S2 are both triggers for the system, if either of them are pressed the thyristor will turn on, thus making the alarm set off. There are 2 switches to allow for multiple alarm points (perhaps one on each door). S3 will turn of the alarm +9)b) in book +9)c) in book +9)d)i) S3 is pressed +9)d)ii) at the start, before Y dips to 0V, the alarm is turned on and the thyristor is conducting, this is because there is 0V over the thyristor, which means all 12V must be over the alarm, turning it on. When S3 is pressed (Y dips to 0V) the alarm will turn off because the thyristor has been reset. It will now have 12V over it until the alarm is triggered again either by S1 or S2 + +10)a)i) this is interference, an unwanted signal being applied over the top of the desired signal, an example of this is a strong magnet, as when moved over a wire, they can change the voltages, thus applying a noise to the signal +10)a)ii) in book +10)b)i) in book +10)b)ii) in book +10)b)iii) in book + diff --git a/electronics/test/2/test.txt b/electronics/test/2/test.txt new file mode 100644 index 0000000..3d7c2fa --- /dev/null +++ b/electronics/test/2/test.txt @@ -0,0 +1,44 @@ +1)a)i) in book +1)a)ii) in book +1)a)iii) in book + +1)b) in book + +1)c)i) in book +1)c)ii) in book +1)c)iii) in book +1)c)iv) in book + +2)a)i) forward +2)a)ii) reverse +2)a)iii) reverse +2)a)iv) forward +2)b) in book +2)c)i) in book +2)c)ii) in book +2)c)iii) in book +2)c)iv) in book + +3)a) in book +3)b) in book + +4)a)i) in book +4)a)ii) I believe it would be close to 0V as the input of 100Hz is very low, and this is a high pass filter meaning only high frequency signals should pass through +4)b) They can have a gain greater than 1, they can be stricter (have a sharper cut off, higher Q factor), than a passive filter +4)c)i) in book +4)c)ii) in book + +5) +- the diode must be between the mesurment middle point and point C, this is because there is 0 current flowing when C is connected to 9V +- you can also tell this because current flows from A-B and B-A just fine +- there is a resistor going from A to the mid point, and from B to the mid point +- the resistor from A to the mid point must be 100 ohms, this is because there R = V/I, we can use the result from A-C (resistor through diode) to tell that V = 9 - 0.7 and the table to tell us that I = 0.083 which gives us 100 ohms +- the resistor from B to the mid point must be 100 ohms, this is because there R = V/I, we can use the result from B-C (resistor through diode) to tell that V = 9 - 0.7 and the table to tell us that I = 0.0415 which gives us 200 ohms +- this can be confirmed by the fact that using the table values fro A-B or B-A, we can say 9/0.3 to get the resistance or Ra + Rb which is 300 ohms, thus confirming our result from before + + + + + + + |